Base | Representation |
---|---|
bin | 1101000000100011101100… |
… | …0100000000100110001000 |
3 | 1212122101010211102201100201 |
4 | 3100020323010000212020 |
5 | 3333321004343034230 |
6 | 50230451501141544 |
7 | 3004242265011523 |
oct | 320107304004610 |
9 | 55571124381321 |
10 | 14303232002440 |
11 | 4614a6a643187 |
12 | 173008b55a8b4 |
13 | 7c9a34547924 |
14 | 3763cc929bba |
15 | 19c0d71cc5ca |
hex | d023b100988 |
14303232002440 has 64 divisors (see below), whose sum is σ = 33913991554560. Its totient is φ = 5418357331200.
The previous prime is 14303232002431. The next prime is 14303232002459. The reversal of 14303232002440 is 4420023230341.
It is a junction number, because it is equal to n+sod(n) for n = 14303232002399 and 14303232002408.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 76872384 + ... + 77058223.
It is an arithmetic number, because the mean of its divisors is an integer number (529906118040).
Almost surely, 214303232002440 is an apocalyptic number.
14303232002440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14303232002440 is an abundant number, since it is smaller than the sum of its proper divisors (19610759552120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14303232002440 is a wasteful number, since it uses less digits than its factorization.
14303232002440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153930742 (or 153930738 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 14303232002440 its reverse (4420023230341), we get a palindrome (18723255232781).
The spelling of 14303232002440 in words is "fourteen trillion, three hundred three billion, two hundred thirty-two million, two thousand, four hundred forty".
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