Base | Representation |
---|---|
bin | 10100110100000110100… |
… | …011111111111111100111 |
3 | 12001201221110011022210222 |
4 | 110310012203333333213 |
5 | 141413311024210043 |
6 | 3013030402034555 |
7 | 205224005120105 |
oct | 24640643777747 |
9 | 5051843138728 |
10 | 1430334210023 |
11 | 501668411254 |
12 | 1b1260048a5b |
13 | a4b592b7084 |
14 | 4d32b1b0c75 |
15 | 273162a3d68 |
hex | 14d068fffe7 |
1430334210023 has 2 divisors, whose sum is σ = 1430334210024. Its totient is φ = 1430334210022.
The previous prime is 1430334210001. The next prime is 1430334210029. The reversal of 1430334210023 is 3200124330341.
It is a strong prime.
It is an emirp because it is prime and its reverse (3200124330341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1430334210023 - 234 = 1413154340839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1430334209974 and 1430334210001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1430334210029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715167105011 + 715167105012.
It is an arithmetic number, because the mean of its divisors is an integer number (715167105012).
Almost surely, 21430334210023 is an apocalyptic number.
1430334210023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1430334210023 is an equidigital number, since it uses as much as digits as its factorization.
1430334210023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 1430334210023 its reverse (3200124330341), we get a palindrome (4630458540364).
The spelling of 1430334210023 in words is "one trillion, four hundred thirty billion, three hundred thirty-four million, two hundred ten thousand, twenty-three".
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