14304420131 has 2 divisors, whose sum is σ = 14304420132. Its totient is φ = 14304420130.

The previous prime is 14304420121. The next prime is 14304420139. The reversal of 14304420131 is 13102440341.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14304420131 is a prime.

It is a super-2 number, since 2×14304420131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14304420097 and 14304420106.

It is not a weakly prime, because it can be changed into another prime (14304420139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7152210065 + 7152210066.

It is an arithmetic number, because the mean of its divisors is an integer number (7152210066).

Almost surely, 2^14304420131 is an apocalyptic number.

14304420131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14304420131 is an equidigital number, since it uses as much as digits as its factorization.

14304420131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14304420131 its reverse (13102440341), we get a palindrome (27406860472).

The spelling of 14304420131 in words is "fourteen billion, three hundred four million, four hundred twenty thousand, one hundred thirty-one".