Base | Representation |
---|---|
bin | 11010101001001110… |
… | …00010000100011001 |
3 | 1100220220021211110211 |
4 | 31110213002010121 |
5 | 213243412420441 |
6 | 10323225211121 |
7 | 1014322364515 |
oct | 152447020431 |
9 | 40826254424 |
10 | 14304420121 |
11 | 6080521612 |
12 | 2932630aa1 |
13 | 146c6c6824 |
14 | 999abb145 |
15 | 58ac16a81 |
hex | 3549c2119 |
14304420121 has 2 divisors, whose sum is σ = 14304420122. Its totient is φ = 14304420120.
The previous prime is 14304420103. The next prime is 14304420131. The reversal of 14304420121 is 12102440341.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8005775625 + 6298644496 = 89475^2 + 79364^2 .
It is a cyclic number.
It is not a de Polignac number, because 14304420121 - 225 = 14270865689 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14304420092 and 14304420101.
It is not a weakly prime, because it can be changed into another prime (14304420131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7152210060 + 7152210061.
It is an arithmetic number, because the mean of its divisors is an integer number (7152210061).
Almost surely, 214304420121 is an apocalyptic number.
It is an amenable number.
14304420121 is a deficient number, since it is larger than the sum of its proper divisors (1).
14304420121 is an equidigital number, since it uses as much as digits as its factorization.
14304420121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 14304420121 its reverse (12102440341), we get a palindrome (26406860462).
The spelling of 14304420121 in words is "fourteen billion, three hundred four million, four hundred twenty thousand, one hundred twenty-one".
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