14305052131 has 4 divisors (see below), whose sum is σ = 14345576712. Its totient is φ = 14264527552.

The previous prime is 14305052123. The next prime is 14305052173. The reversal of 14305052131 is 13125050341.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13125050341 = 13 ⋅1009619257.

It is a cyclic number.

It is not a de Polignac number, because 14305052131 - 2³ = 14305052123 is a prime.

It is a super-2 number, since 2×14305052131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14305052096 and 14305052105.

It is not an unprimeable number, because it can be changed into a prime (14305052191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20261761 + ... + 20262466.

It is an arithmetic number, because the mean of its divisors is an integer number (3586394178).

Almost surely, 2^14305052131 is an apocalyptic number.

14305052131 is a deficient number, since it is larger than the sum of its proper divisors (40524581).

14305052131 is an equidigital number, since it uses as much as digits as its factorization.

14305052131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40524580.

The product of its (nonzero) digits is 1800, while the sum is 25.

The spelling of 14305052131 in words is "fourteen billion, three hundred five million, fifty-two thousand, one hundred thirty-one".