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14305211030147 is a prime number
BaseRepresentation
bin1101000000101011000100…
…0001011001101010000011
31212122120020202022202000012
43100022301001121222003
53333334033010431042
650231420114415135
73004342315324562
oct320126101315203
955576222282005
1014305211030147
114615895765a74
1217305422914ab
137c9c8b55b13b
143765396c5bd9
1519c1a0ceae82
hexd02b1059a83

14305211030147 has 2 divisors, whose sum is σ = 14305211030148. Its totient is φ = 14305211030146.

The previous prime is 14305211030111. The next prime is 14305211030171. The reversal of 14305211030147 is 74103011250341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14305211030147 - 226 = 14305143921283 is a prime.

It is not a weakly prime, because it can be changed into another prime (14305211030647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7152605515073 + 7152605515074.

It is an arithmetic number, because the mean of its divisors is an integer number (7152605515074).

Almost surely, 214305211030147 is an apocalyptic number.

14305211030147 is a deficient number, since it is larger than the sum of its proper divisors (1).

14305211030147 is an equidigital number, since it uses as much as digits as its factorization.

14305211030147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 32.

Adding to 14305211030147 its reverse (74103011250341), we get a palindrome (88408222280488).

The spelling of 14305211030147 in words is "fourteen trillion, three hundred five billion, two hundred eleven million, thirty thousand, one hundred forty-seven".