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14306131200 = 283525973173
BaseRepresentation
bin11010101001011011…
…00011110100000000
31100221000111202122010
431110231203310000
5213244332144300
610323330012520
71014343052214
oct152455436400
940830452563
1014306131200
116081490129
122933117140
13146cb755ba
1499a004944
1558ae53a50
hex354b63d00

14306131200 has 432 divisors, whose sum is σ = 48952491840. Its totient is φ = 3677552640.

The previous prime is 14306131199. The next prime is 14306131247. The reversal of 14306131200 is 213160341.

It is a super-2 number, since 2×143061312002 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 82694314 + ... + 82694486.

Almost surely, 214306131200 is an apocalyptic number.

14306131200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14306131200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24476245920).

14306131200 is an abundant number, since it is smaller than the sum of its proper divisors (34646360640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14306131200 is a wasteful number, since it uses less digits than its factorization.

14306131200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 334 (or 315 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 14306131200 its reverse (213160341), we get a palindrome (14519291541).

The spelling of 14306131200 in words is "fourteen billion, three hundred six million, one hundred thirty-one thousand, two hundred".