Base | Representation |
---|---|
bin | 10100110100011101110… |
… | …000000010011001001111 |
3 | 12001202221120012011202002 |
4 | 110310131300002121033 |
5 | 141420110122212201 |
6 | 3013133140222515 |
7 | 205236440616602 |
oct | 24643560023117 |
9 | 5052846164662 |
10 | 1430723241551 |
11 | 501847a7540a |
12 | 1b134a39aa3b |
13 | a4bbba88046 |
14 | 4d366b1c339 |
15 | 2733a4ec76b |
hex | 14d1dc0264f |
1430723241551 has 4 divisors (see below), whose sum is σ = 1461164161632. Its totient is φ = 1400282321472.
The previous prime is 1430723241547. The next prime is 1430723241557. The reversal of 1430723241551 is 1551423270341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1430723241551 - 22 = 1430723241547 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1430723241557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15220459970 + ... + 15220460063.
It is an arithmetic number, because the mean of its divisors is an integer number (365291040408).
Almost surely, 21430723241551 is an apocalyptic number.
1430723241551 is a deficient number, since it is larger than the sum of its proper divisors (30440920081).
1430723241551 is an equidigital number, since it uses as much as digits as its factorization.
1430723241551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30440920080.
The product of its (nonzero) digits is 100800, while the sum is 38.
The spelling of 1430723241551 in words is "one trillion, four hundred thirty billion, seven hundred twenty-three million, two hundred forty-one thousand, five hundred fifty-one".
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