Base | Representation |
---|---|
bin | 100000100010011000010001… |
… | …111000010001001011001110 |
3 | 200202200020011110102002110221 |
4 | 200202120101320101023032 |
5 | 122224022320201044324 |
6 | 1224203124121221554 |
7 | 42066430622240302 |
oct | 4042302170211316 |
9 | 622606143362427 |
10 | 143100020331214 |
11 | 4166141795a181 |
12 | 140718ab3318ba |
13 | 61b037401b12b |
14 | 274a113c17d02 |
15 | 118255eb340e4 |
hex | 822611e112ce |
143100020331214 has 4 divisors (see below), whose sum is σ = 214650030496824. Its totient is φ = 71550010165606.
The previous prime is 143100020331173. The next prime is 143100020331239. The reversal of 143100020331214 is 412133020001341.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35775005082802 + ... + 35775005082805.
It is an arithmetic number, because the mean of its divisors is an integer number (53662507624206).
Almost surely, 2143100020331214 is an apocalyptic number.
143100020331214 is a deficient number, since it is larger than the sum of its proper divisors (71550010165610).
143100020331214 is an equidigital number, since it uses as much as digits as its factorization.
143100020331214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71550010165609.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 143100020331214 its reverse (412133020001341), we get a palindrome (555233040332555).
The spelling of 143100020331214 in words is "one hundred forty-three trillion, one hundred billion, twenty million, three hundred thirty-one thousand, two hundred fourteen".
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