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1431001012 = 227137337223
BaseRepresentation
bin101010101001011…
…0101011110110100
310200201200101100111
41111102311132310
510412314013022
6353555152404
750314210420
oct12522653664
93621611314
101431001012
11674843271
1233b2a5704
1319a61427c
14d80a1b80
158596a477
hex554b57b4

1431001012 has 24 divisors (see below), whose sum is σ = 2864163456. Its totient is φ = 612823008.

The previous prime is 1431000973. The next prime is 1431001037. The reversal of 1431001012 is 2101001341.

It is a junction number, because it is equal to n+sod(n) for n = 1431000983 and 1431001001.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19833 + ... + 57055.

It is an arithmetic number, because the mean of its divisors is an integer number (119340144).

Almost surely, 21431001012 is an apocalyptic number.

It is an amenable number.

1431001012 is an abundant number, since it is smaller than the sum of its proper divisors (1433162444).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1431001012 is a wasteful number, since it uses less digits than its factorization.

1431001012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38607 (or 38605 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1431001012 is about 37828.5740148899. The cubic root of 1431001012 is about 1126.8859919099.

Adding to 1431001012 its reverse (2101001341), we get a palindrome (3532002353).

The spelling of 1431001012 in words is "one billion, four hundred thirty-one million, one thousand, twelve".

Divisors: 1 2 4 7 14 28 1373 2746 5492 9611 19222 37223 38444 74446 148892 260561 521122 1042244 51107179 102214358 204428716 357750253 715500506 1431001012