Base | Representation |
---|---|
bin | 1000010101000101101… |
… | …1101011011011001111 |
3 | 111200100220010212000201 |
4 | 2011101123223123033 |
5 | 4321032113143043 |
6 | 145423404234331 |
7 | 13224104021113 |
oct | 2052133533317 |
9 | 450326125021 |
10 | 143100131023 |
11 | 557633254a3 |
12 | 23897b3b9a7 |
13 | 10656c34855 |
14 | 6cd725b743 |
15 | 3ac7e93c4d |
hex | 21516eb6cf |
143100131023 has 2 divisors, whose sum is σ = 143100131024. Its totient is φ = 143100131022.
The previous prime is 143100131011. The next prime is 143100131063. The reversal of 143100131023 is 320131001341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143100131023 - 213 = 143100122831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143100131063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71550065511 + 71550065512.
It is an arithmetic number, because the mean of its divisors is an integer number (71550065512).
Almost surely, 2143100131023 is an apocalyptic number.
143100131023 is a deficient number, since it is larger than the sum of its proper divisors (1).
143100131023 is an equidigital number, since it uses as much as digits as its factorization.
143100131023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 143100131023 its reverse (320131001341), we get a palindrome (463231132364).
The spelling of 143100131023 in words is "one hundred forty-three billion, one hundred million, one hundred thirty-one thousand, twenty-three".
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