143101314101 has 2 divisors, whose sum is σ = 143101314102. Its totient is φ = 143101314100.

The previous prime is 143101314067. The next prime is 143101314107. The reversal of 143101314101 is 101413101341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103391187025 + 39710127076 = 321545^2 + 199274^2 .

It is an emirp because it is prime and its reverse (101413101341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143101314101 - 2¹⁰ = 143101313077 is a prime.

It is a super-2 number, since 2×143101314101² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143101314107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71550657050 + 71550657051.

It is an arithmetic number, because the mean of its divisors is an integer number (71550657051).

Almost surely, 2^143101314101 is an apocalyptic number.

It is an amenable number.

143101314101 is a deficient number, since it is larger than the sum of its proper divisors (1).

143101314101 is an equidigital number, since it uses as much as digits as its factorization.

143101314101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 143101314101 its reverse (101413101341), we get a palindrome (244514415442).

The spelling of 143101314101 in words is "one hundred forty-three billion, one hundred one million, three hundred fourteen thousand, one hundred one".