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14310240414112 = 25447195012941
BaseRepresentation
bin1101000000111101110011…
…0010111110100110100000
31212200001020020222220210101
43100033130302332212200
53333424333021222422
650234011135512144
73004611045353566
oct320173462764640
955601206886711
1014310240414112
114617a36712645
121731506688654
137ca5b0507496
14376895635a36
1519c397608c27
hexd03dccbe9a0

14310240414112 has 12 divisors (see below), whose sum is σ = 28173285815346. Its totient is φ = 7155120207040.

The previous prime is 14310240414103. The next prime is 14310240414137. The reversal of 14310240414112 is 21141404201341.

It is a happy number.

14310240414112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 12078933426576 + 2231306987536 = 3475476^2 + 1493756^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 223597506439 + ... + 223597506502.

Almost surely, 214310240414112 is an apocalyptic number.

It is an amenable number.

14310240414112 is a deficient number, since it is larger than the sum of its proper divisors (13863045401234).

14310240414112 is an equidigital number, since it uses as much as digits as its factorization.

14310240414112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 447195012951 (or 447195012943 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 14310240414112 its reverse (21141404201341), we get a palindrome (35451644615453).

The spelling of 14310240414112 in words is "fourteen trillion, three hundred ten billion, two hundred forty million, four hundred fourteen thousand, one hundred twelve".

Divisors: 1 2 4 8 16 32 447195012941 894390025882 1788780051764 3577560103528 7155120207056 14310240414112