Base | Representation |
---|---|
bin | 1000010101000110101… |
… | …0100001011011101101 |
3 | 111200101011110112210100 |
4 | 2011101222201123231 |
5 | 4321034112203003 |
6 | 145424023501313 |
7 | 13224152055603 |
oct | 2052152413355 |
9 | 450334415710 |
10 | 143104022253 |
11 | 55765542a95 |
12 | 238992b7839 |
13 | 10657997a5a |
14 | 6cd7991873 |
15 | 3ac84b1ba3 |
hex | 2151aa16ed |
143104022253 has 24 divisors (see below), whose sum is σ = 223130718720. Its totient is φ = 88108020000.
The previous prime is 143104022221. The next prime is 143104022261. The reversal of 143104022253 is 352220401341.
143104022253 is a `hidden beast` number, since 1 + 4 + 3 + 1 + 0 + 402 + 2 + 253 = 666.
It is not a de Polignac number, because 143104022253 - 25 = 143104022221 is a prime.
It is a super-2 number, since 2×1431040222532 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143104022153) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11913373 + ... + 11925378.
It is an arithmetic number, because the mean of its divisors is an integer number (9297113280).
Almost surely, 2143104022253 is an apocalyptic number.
It is an amenable number.
143104022253 is a deficient number, since it is larger than the sum of its proper divisors (80026696467).
143104022253 is a wasteful number, since it uses less digits than its factorization.
143104022253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23838809 (or 23838806 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 143104022253 its reverse (352220401341), we get a palindrome (495324423594).
The spelling of 143104022253 in words is "one hundred forty-three billion, one hundred four million, twenty-two thousand, two hundred fifty-three".
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