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14310413143 = 135743191677
BaseRepresentation
bin11010101001111011…
…11001001101010111
31100221022120022100121
431110331321031113
5213301431210033
610324001452411
71014424335055
oct152475711527
940838508317
1014310413143
116083945224
122934641107
131470a145b0
1499a7db1d5
1558b4ec62d
hex354f79357

14310413143 has 8 divisors (see below), whose sum is σ = 15413978048. Its totient is φ = 13207243104.

The previous prime is 14310413113. The next prime is 14310413191. The reversal of 14310413143 is 34131401341.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14310413143 - 29 = 14310412631 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14310413113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21180 + ... + 170497.

It is an arithmetic number, because the mean of its divisors is an integer number (1926747256).

Almost surely, 214310413143 is an apocalyptic number.

14310413143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

14310413143 is a deficient number, since it is larger than the sum of its proper divisors (1103564905).

14310413143 is a wasteful number, since it uses less digits than its factorization.

14310413143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 197433.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 14310413143 its reverse (34131401341), we get a palindrome (48441814484).

The spelling of 14310413143 in words is "fourteen billion, three hundred ten million, four hundred thirteen thousand, one hundred forty-three".

Divisors: 1 13 5743 74659 191677 2491801 1100801011 14310413143