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14311013 is a prime number
BaseRepresentation
bin110110100101…
…111001100101
3222221002000112
4312211321211
512130423023
61230422405
7232433033
oct66457145
928832015
1014311013
118095092
124961a05
132c70b72
141c87553
1513ca478
hexda5e65

14311013 has 2 divisors, whose sum is σ = 14311014. Its totient is φ = 14311012.

The previous prime is 14310997. The next prime is 14311019. The reversal of 14311013 is 31011341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13667809 + 643204 = 3697^2 + 802^2 .

It is an emirp because it is prime and its reverse (31011341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14311013 - 24 = 14310997 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14311019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155506 + 7155507.

It is an arithmetic number, because the mean of its divisors is an integer number (7155507).

Almost surely, 214311013 is an apocalyptic number.

It is an amenable number.

14311013 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311013 is an equidigital number, since it uses as much as digits as its factorization.

14311013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 14311013 is about 3782.9899550488. The cubic root of 14311013 is about 242.7858986769.

Adding to 14311013 its reverse (31011341), we get a palindrome (45322354).

The spelling of 14311013 in words is "fourteen million, three hundred eleven thousand, thirteen".