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143110342 = 271555171
BaseRepresentation
bin10001000011110…
…11000011000110
3100222021202111001
420201323003012
5243114012332
622111203514
73355263214
oct1041730306
9328252431
10143110342
1173866a11
123bb1659a
1323858c9b
1415013cb4
15c86d0e7
hex887b0c6

143110342 has 4 divisors (see below), whose sum is σ = 214665516. Its totient is φ = 71555170.

The previous prime is 143110313. The next prime is 143110349. The reversal of 143110342 is 243011341.

143110342 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 243011341 = 538145161.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143110349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35777584 + ... + 35777587.

It is an arithmetic number, because the mean of its divisors is an integer number (53666379).

Almost surely, 2143110342 is an apocalyptic number.

143110342 is a deficient number, since it is larger than the sum of its proper divisors (71555174).

143110342 is an equidigital number, since it uses as much as digits as its factorization.

143110342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71555173.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 143110342 is about 11962.8734842428. The cubic root of 143110342 is about 523.0666206459.

Adding to 143110342 its reverse (243011341), we get a palindrome (386121683).

Subtracting 143110342 from its reverse (243011341), we obtain a palindrome (99900999).

The spelling of 143110342 in words is "one hundred forty-three million, one hundred ten thousand, three hundred forty-two".

Divisors: 1 2 71555171 143110342