Search a number
-
+
14311227230 = 251431122723
BaseRepresentation
bin11010101010000001…
…11111111101011110
31100221101002200001222
431111000333331132
5213302133232410
610324031133342
71014434265356
oct152500777536
940841080058
1014311227230
116084350923
122934974252
131470c3acc1
1499a96db66
1558b60d955
hex35503ff5e

14311227230 has 8 divisors (see below), whose sum is σ = 25760209032. Its totient is φ = 5724490888.

The previous prime is 14311227223. The next prime is 14311227241. The reversal of 14311227230 is 3272211341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×143112272303 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 14311227230.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 715561352 + ... + 715561371.

It is an arithmetic number, because the mean of its divisors is an integer number (3220026129).

Almost surely, 214311227230 is an apocalyptic number.

14311227230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14311227230 is a deficient number, since it is larger than the sum of its proper divisors (11448981802).

14311227230 is a wasteful number, since it uses less digits than its factorization.

14311227230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1431122730.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 14311227230 its reverse (3272211341), we get a palindrome (17583438571).

The spelling of 14311227230 in words is "fourteen billion, three hundred eleven million, two hundred twenty-seven thousand, two hundred thirty".

Divisors: 1 2 5 10 1431122723 2862245446 7155613615 14311227230