Base | Representation |
---|---|
bin | 11010101010000010… |
… | …00000101010110101 |
3 | 1100221101002211001111 |
4 | 31111001000222311 |
5 | 213302133331013 |
6 | 10324031155021 |
7 | 1014434310004 |
oct | 152501005265 |
9 | 40841084044 |
10 | 14311230133 |
11 | 6084353022 |
12 | 2934975a71 |
13 | 1470c3c415 |
14 | 99a970c3b |
15 | 58b60e73d |
hex | 355040ab5 |
14311230133 has 2 divisors, whose sum is σ = 14311230134. Its totient is φ = 14311230132.
The previous prime is 14311230119. The next prime is 14311230149. The reversal of 14311230133 is 33103211341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14294115364 + 17114769 = 119558^2 + 4137^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14311230133 is a prime.
It is a super-2 number, since 2×143112301332 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14311236133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155615066 + 7155615067.
It is an arithmetic number, because the mean of its divisors is an integer number (7155615067).
Almost surely, 214311230133 is an apocalyptic number.
It is an amenable number.
14311230133 is a deficient number, since it is larger than the sum of its proper divisors (1).
14311230133 is an equidigital number, since it uses as much as digits as its factorization.
14311230133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 14311230133 its reverse (33103211341), we get a palindrome (47414441474).
The spelling of 14311230133 in words is "fourteen billion, three hundred eleven million, two hundred thirty thousand, one hundred thirty-three".
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