Base | Representation |
---|---|
bin | 1000010101001000101… |
… | …0101000111000011011 |
3 | 111200101202022021122112 |
4 | 2011102022220320123 |
5 | 4321043241110441 |
6 | 145424524142535 |
7 | 13224313452254 |
oct | 2052212507033 |
9 | 450352267575 |
10 | 143112441371 |
11 | 5576a273439 |
12 | 238a0097a4b |
13 | 10659654b93 |
14 | 6cd8b43b2b |
15 | 3ac90c64eb |
hex | 21522a8e1b |
143112441371 has 2 divisors, whose sum is σ = 143112441372. Its totient is φ = 143112441370.
The previous prime is 143112441361. The next prime is 143112441413. The reversal of 143112441371 is 173144211341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143112441371 - 230 = 142038699547 is a prime.
It is a super-3 number, since 3×1431124413713 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (143112441331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71556220685 + 71556220686.
It is an arithmetic number, because the mean of its divisors is an integer number (71556220686).
Almost surely, 2143112441371 is an apocalyptic number.
143112441371 is a deficient number, since it is larger than the sum of its proper divisors (1).
143112441371 is an equidigital number, since it uses as much as digits as its factorization.
143112441371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8064, while the sum is 32.
The spelling of 143112441371 in words is "one hundred forty-three billion, one hundred twelve million, four hundred forty-one thousand, three hundred seventy-one".
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