1431130231 has 2 divisors, whose sum is σ = 1431130232. Its totient is φ = 1431130230.

The previous prime is 1431130199. The next prime is 1431130237. The reversal of 1431130231 is 1320311341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1431130231 - 2⁵ = 1431130199 is a prime.

It is a super-2 number, since 2×1431130231² = 4096267476164226722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1431130199 and 1431130208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1431130237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715565115 + 715565116.

It is an arithmetic number, because the mean of its divisors is an integer number (715565116).

Almost surely, 2^1431130231 is an apocalyptic number.

1431130231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431130231 is an equidigital number, since it uses as much as digits as its factorization.

1431130231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1431130231 is about 37830.2819312783. The cubic root of 1431130231 is about 1126.9199100547.

Adding to 1431130231 its reverse (1320311341), we get a palindrome (2751441572).

The spelling of 1431130231 in words is "one billion, four hundred thirty-one million, one hundred thirty thousand, two hundred thirty-one".