1431131241011 has 2 divisors, whose sum is σ = 1431131241012. Its totient is φ = 1431131241010.

The previous prime is 1431131240963. The next prime is 1431131241013. The reversal of 1431131241011 is 1101421311341.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1431131241011 is a prime.

Together with 1431131241013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1431131241013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715565620505 + 715565620506.

It is an arithmetic number, because the mean of its divisors is an integer number (715565620506).

Almost surely, 2^{1431131241011} is an apocalyptic number.

1431131241011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431131241011 is an equidigital number, since it uses as much as digits as its factorization.

1431131241011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 1431131241011 its reverse (1101421311341), we get a palindrome (2532552552352).

The spelling of 1431131241011 in words is "one trillion, four hundred thirty-one billion, one hundred thirty-one million, two hundred forty-one thousand, eleven".