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14311345141 is a prime number
BaseRepresentation
bin11010101010000010…
…11100101111110101
31100221101022122211001
431111001130233311
5213302201021031
610324033443301
71014435266212
oct152501345765
940841278731
1014311345141
116084421475
122934a10531
131470c7c882
1499a9a0b09
1558b633861
hex35505cbf5

14311345141 has 2 divisors, whose sum is σ = 14311345142. Its totient is φ = 14311345140.

The previous prime is 14311345133. The next prime is 14311345151. The reversal of 14311345141 is 14154311341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13523364100 + 787981041 = 116290^2 + 28071^2 .

It is an emirp because it is prime and its reverse (14154311341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14311345141 - 23 = 14311345133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14311345121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155672570 + 7155672571.

It is an arithmetic number, because the mean of its divisors is an integer number (7155672571).

Almost surely, 214311345141 is an apocalyptic number.

It is an amenable number.

14311345141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311345141 is an equidigital number, since it uses as much as digits as its factorization.

14311345141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2880, while the sum is 28.

Adding to 14311345141 its reverse (14154311341), we get a palindrome (28465656482).

The spelling of 14311345141 in words is "fourteen billion, three hundred eleven million, three hundred forty-five thousand, one hundred forty-one".