Base | Representation |
---|---|
bin | 1101000001000010101010… |
… | …0000111010110000001111 |
3 | 1212200011121010111022112212 |
4 | 3100100222200322300033 |
5 | 3333440020320140412 |
6 | 50234344354421035 |
7 | 3004655260261016 |
oct | 320205240726017 |
9 | 55604533438485 |
10 | 14311544302607 |
11 | 4618545726342 |
12 | 173180b29177b |
13 | 7ca75a6a4336 |
14 | 37697a889a7d |
15 | 19c421d16222 |
hex | d042a83ac0f |
14311544302607 has 2 divisors, whose sum is σ = 14311544302608. Its totient is φ = 14311544302606.
The previous prime is 14311544302579. The next prime is 14311544302661. The reversal of 14311544302607 is 70620344511341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14311544302607 - 214 = 14311544286223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14311544302667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155772151303 + 7155772151304.
It is an arithmetic number, because the mean of its divisors is an integer number (7155772151304).
Almost surely, 214311544302607 is an apocalyptic number.
14311544302607 is a deficient number, since it is larger than the sum of its proper divisors (1).
14311544302607 is an equidigital number, since it uses as much as digits as its factorization.
14311544302607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 41.
Adding to 14311544302607 its reverse (70620344511341), we get a palindrome (84931888813948).
The spelling of 14311544302607 in words is "fourteen trillion, three hundred eleven billion, five hundred forty-four million, three hundred two thousand, six hundred seven".
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