14312031341 has 2 divisors, whose sum is σ = 14312031342. Its totient is φ = 14312031340.

The previous prime is 14312031319. The next prime is 14312031413. The reversal of 14312031341 is 14313021341.

Together with next prime (14312031413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12022026025 + 2290005316 = 109645^2 + 47854^2 .

It is an emirp because it is prime and its reverse (14313021341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14312031341 is a prime.

It is a super-2 number, since 2×14312031341² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14312031301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156015670 + 7156015671.

It is an arithmetic number, because the mean of its divisors is an integer number (7156015671).

Almost surely, 2^14312031341 is an apocalyptic number.

It is an amenable number.

14312031341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312031341 is an equidigital number, since it uses as much as digits as its factorization.

14312031341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 14312031341 its reverse (14313021341), we get a palindrome (28625052682).

The spelling of 14312031341 in words is "fourteen billion, three hundred twelve million, thirty-one thousand, three hundred forty-one".