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143120344351 is a prime number
BaseRepresentation
bin1000010101001010100…
…0110010010100011111
3111200102022011210111111
42011102220302110133
54321102302004401
6145425405402451
713224440566105
oct2052250622437
9450368153444
10143120344351
1155773781026
12238a2869427
131065b1910ba
146cd9bddc75
153ac9b37e51
hex2152a3251f

143120344351 has 2 divisors, whose sum is σ = 143120344352. Its totient is φ = 143120344350.

The previous prime is 143120344303. The next prime is 143120344453. The reversal of 143120344351 is 153443021341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 143120344351 - 211 = 143120342303 is a prime.

It is a super-2 number, since 2×1431203443512 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143120344151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71560172175 + 71560172176.

It is an arithmetic number, because the mean of its divisors is an integer number (71560172176).

Almost surely, 2143120344351 is an apocalyptic number.

143120344351 is a deficient number, since it is larger than the sum of its proper divisors (1).

143120344351 is an equidigital number, since it uses as much as digits as its factorization.

143120344351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 143120344351 its reverse (153443021341), we get a palindrome (296563365692).

The spelling of 143120344351 in words is "one hundred forty-three billion, one hundred twenty million, three hundred forty-four thousand, three hundred fifty-one".