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14312053153 is a prime number
BaseRepresentation
bin11010101010001000…
…01001100110100001
31100221102122122000201
431111010021212201
5213302341200103
610324100545201
71014444305326
oct152504114641
940842578021
1014312053153
116084865402
1229350b2201
131471169c08
1499ab06b4d
1558b72351d
hex3551099a1

14312053153 has 2 divisors, whose sum is σ = 14312053154. Its totient is φ = 14312053152.

The previous prime is 14312053099. The next prime is 14312053201. The reversal of 14312053153 is 35135021341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14025191184 + 286861969 = 118428^2 + 16937^2 .

It is a cyclic number.

It is not a de Polignac number, because 14312053153 - 29 = 14312052641 is a prime.

It is not a weakly prime, because it can be changed into another prime (14312053453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156026576 + 7156026577.

It is an arithmetic number, because the mean of its divisors is an integer number (7156026577).

Almost surely, 214312053153 is an apocalyptic number.

It is an amenable number.

14312053153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312053153 is an equidigital number, since it uses as much as digits as its factorization.

14312053153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 14312053153 its reverse (35135021341), we get a palindrome (49447074494).

The spelling of 14312053153 in words is "fourteen billion, three hundred twelve million, fifty-three thousand, one hundred fifty-three".