Base | Representation |
---|---|
bin | 10100110100111010101… |
… | …001000011000010101101 |
3 | 12001211012100020211121212 |
4 | 110310322221003002231 |
5 | 141422103213322321 |
6 | 3013253213204205 |
7 | 205254444560354 |
oct | 24647251030255 |
9 | 5054170224555 |
10 | 1431207948461 |
11 | 501a76636935 |
12 | 1b1464790665 |
13 | a4c68317275 |
14 | 4d3b125299b |
15 | 27367d4455b |
hex | 14d3aa430ad |
1431207948461 has 2 divisors, whose sum is σ = 1431207948462. Its totient is φ = 1431207948460.
The previous prime is 1431207948437. The next prime is 1431207948481. The reversal of 1431207948461 is 1648497021341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1424635603561 + 6572344900 = 1193581^2 + 81070^2 .
It is a cyclic number.
It is not a de Polignac number, because 1431207948461 - 210 = 1431207947437 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1431207948481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715603974230 + 715603974231.
It is an arithmetic number, because the mean of its divisors is an integer number (715603974231).
Almost surely, 21431207948461 is an apocalyptic number.
It is an amenable number.
1431207948461 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431207948461 is an equidigital number, since it uses as much as digits as its factorization.
1431207948461 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1161216, while the sum is 50.
The spelling of 1431207948461 in words is "one trillion, four hundred thirty-one billion, two hundred seven million, nine hundred forty-eight thousand, four hundred sixty-one".
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