Base | Representation |
---|---|
bin | 11010101010001000… |
… | …11110110100001011 |
3 | 1100221102211001012212 |
4 | 31111010132310023 |
5 | 213302401440133 |
6 | 10324102455335 |
7 | 1014445116545 |
oct | 152504366413 |
9 | 40842731185 |
10 | 14312140043 |
11 | 6084914713 |
12 | 293513454b |
13 | 147119a626 |
14 | 99ab2a695 |
15 | 58b73e148 |
hex | 35511ed0b |
14312140043 has 2 divisors, whose sum is σ = 14312140044. Its totient is φ = 14312140042.
The previous prime is 14312140021. The next prime is 14312140079. The reversal of 14312140043 is 34004121341.
14312140043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14312140043 - 210 = 14312139019 is a prime.
It is a super-2 number, since 2×143121400432 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14312140343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156070021 + 7156070022.
It is an arithmetic number, because the mean of its divisors is an integer number (7156070022).
Almost surely, 214312140043 is an apocalyptic number.
14312140043 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312140043 is an equidigital number, since it uses as much as digits as its factorization.
14312140043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 14312140043 its reverse (34004121341), we get a palindrome (48316261384).
The spelling of 14312140043 in words is "fourteen billion, three hundred twelve million, one hundred forty thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •