Base | Representation |
---|---|
bin | 11010101010001000… |
… | …11110110011110101 |
3 | 1100221102211001012001 |
4 | 31111010132303311 |
5 | 213302401440041 |
6 | 10324102455301 |
7 | 1014445116514 |
oct | 152504366365 |
9 | 40842731161 |
10 | 14312140021 |
11 | 60849146a3 |
12 | 2935134531 |
13 | 147119a60a |
14 | 99ab2a67b |
15 | 58b73e131 |
hex | 35511ecf5 |
14312140021 has 2 divisors, whose sum is σ = 14312140022. Its totient is φ = 14312140020.
The previous prime is 14312139997. The next prime is 14312140043. The reversal of 14312140021 is 12004121341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14310140625 + 1999396 = 119625^2 + 1414^2 .
It is a cyclic number.
It is not a de Polignac number, because 14312140021 - 213 = 14312131829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14312140721) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156070010 + 7156070011.
It is an arithmetic number, because the mean of its divisors is an integer number (7156070011).
Almost surely, 214312140021 is an apocalyptic number.
It is an amenable number.
14312140021 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312140021 is an equidigital number, since it uses as much as digits as its factorization.
14312140021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 14312140021 its reverse (12004121341), we get a palindrome (26316261362).
The spelling of 14312140021 in words is "fourteen billion, three hundred twelve million, one hundred forty thousand, twenty-one".
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