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143122110389 is a prime number
BaseRepresentation
bin1000010101001010111…
…1100001011110110101
3111200102102111112001022
42011102233201132311
54321103230013024
6145425511310525
713224461602646
oct2052257413665
9450372445038
10143122110389
1155774777965
12238a337b445
131065b65bbab
146cda13d6cd
153ac9d8635e
hex2152be17b5

143122110389 has 2 divisors, whose sum is σ = 143122110390. Its totient is φ = 143122110388.

The previous prime is 143122110359. The next prime is 143122110413. The reversal of 143122110389 is 983011221341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122258619025 + 20863491364 = 349655^2 + 144442^2 .

It is an emirp because it is prime and its reverse (983011221341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143122110389 - 232 = 138827143093 is a prime.

It is a super-2 number, since 2×1431221103892 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143122110359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71561055194 + 71561055195.

It is an arithmetic number, because the mean of its divisors is an integer number (71561055195).

Almost surely, 2143122110389 is an apocalyptic number.

It is an amenable number.

143122110389 is a deficient number, since it is larger than the sum of its proper divisors (1).

143122110389 is an equidigital number, since it uses as much as digits as its factorization.

143122110389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 35.

The spelling of 143122110389 in words is "one hundred forty-three billion, one hundred twenty-two million, one hundred ten thousand, three hundred eighty-nine".