Base | Representation |
---|---|
bin | 11010101010001001… |
… | …10111001110010101 |
3 | 1100221110000010100202 |
4 | 31111010313032111 |
5 | 213302413140041 |
6 | 10324104550245 |
7 | 1014446014202 |
oct | 152504671625 |
9 | 40843003322 |
10 | 14312240021 |
11 | 6084982842 |
12 | 2935182385 |
13 | 1471203ca1 |
14 | 99ab54ca9 |
15 | 58b75da9b |
hex | 355137395 |
14312240021 has 2 divisors, whose sum is σ = 14312240022. Its totient is φ = 14312240020.
The previous prime is 14312240017. The next prime is 14312240027. The reversal of 14312240021 is 12004221341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10974867121 + 3337372900 = 104761^2 + 57770^2 .
It is a cyclic number.
It is not a de Polignac number, because 14312240021 - 22 = 14312240017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14312239975 and 14312240002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14312240027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156120010 + 7156120011.
It is an arithmetic number, because the mean of its divisors is an integer number (7156120011).
Almost surely, 214312240021 is an apocalyptic number.
It is an amenable number.
14312240021 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312240021 is an equidigital number, since it uses as much as digits as its factorization.
14312240021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 14312240021 its reverse (12004221341), we get a palindrome (26316461362).
The spelling of 14312240021 in words is "fourteen billion, three hundred twelve million, two hundred forty thousand, twenty-one".
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