Base | Representation |
---|---|
bin | 1101000001000101010011… |
… | …1100111000111110000001 |
3 | 1212200020102202012102201201 |
4 | 3100101110330320332001 |
5 | 3333443000101402101 |
6 | 50234543150501201 |
7 | 3005012024051134 |
oct | 320212474707601 |
9 | 55606382172651 |
10 | 14312256278401 |
11 | 4618880605294 |
12 | 1731989804801 |
13 | 7ca8420476a3 |
14 | 376a0726021b |
15 | 19c4645a1e01 |
hex | d0454f38f81 |
14312256278401 has 2 divisors, whose sum is σ = 14312256278402. Its totient is φ = 14312256278400.
The previous prime is 14312256278381. The next prime is 14312256278471. The reversal of 14312256278401 is 10487265221341.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14287379418225 + 24876860176 = 3779865^2 + 157724^2 .
It is a cyclic number.
It is not a de Polignac number, because 14312256278401 - 239 = 13762500464513 is a prime.
It is not a weakly prime, because it can be changed into another prime (14312256278471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156128139200 + 7156128139201.
It is an arithmetic number, because the mean of its divisors is an integer number (7156128139201).
Almost surely, 214312256278401 is an apocalyptic number.
It is an amenable number.
14312256278401 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312256278401 is an equidigital number, since it uses as much as digits as its factorization.
14312256278401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 645120, while the sum is 46.
The spelling of 14312256278401 in words is "fourteen trillion, three hundred twelve billion, two hundred fifty-six million, two hundred seventy-eight thousand, four hundred one".
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