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14312289689 is a prime number
BaseRepresentation
bin11010101010001010…
…00011010110011001
31100221110002122111022
431111011003112121
5213302421232224
610324110012225
71014446312045
oct152505032631
940843078438
1014312289689
116084a07095
1229351a7075
131471220789
1499ab69025
1558b76d65e
hex355143599

14312289689 has 2 divisors, whose sum is σ = 14312289690. Its totient is φ = 14312289688.

The previous prime is 14312289659. The next prime is 14312289701. The reversal of 14312289689 is 98698221341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7835259289 + 6477030400 = 88517^2 + 80480^2 .

It is an emirp because it is prime and its reverse (98698221341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14312289689 - 228 = 14043854233 is a prime.

It is a super-2 number, since 2×143122896892 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14312289689.

It is not a weakly prime, because it can be changed into another prime (14312289659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156144844 + 7156144845.

It is an arithmetic number, because the mean of its divisors is an integer number (7156144845).

Almost surely, 214312289689 is an apocalyptic number.

It is an amenable number.

14312289689 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312289689 is an equidigital number, since it uses as much as digits as its factorization.

14312289689 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1492992, while the sum is 53.

The spelling of 14312289689 in words is "fourteen billion, three hundred twelve million, two hundred eighty-nine thousand, six hundred eighty-nine".