143123321341 has 48 divisors (see below), whose sum is σ = 195711683328. Its totient is φ = 102885552000.

The previous prime is 143123321333. The next prime is 143123321357.

143123321341 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 143123321341 - 2³ = 143123321333 is a prime.

It is a super-2 number, since 2×143123321341² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143123321321) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 14450491 + ... + 14460391.

It is an arithmetic number, because the mean of its divisors is an integer number (4077326736).

Almost surely, 2^143123321341 is an apocalyptic number.

143123321341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

143123321341 is a deficient number, since it is larger than the sum of its proper divisors (52588361987).

143123321341 is a wasteful number, since it uses less digits than its factorization.

143123321341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12002 (or 11995 counting only the distinct ones).

The product of its digits is 5184, while the sum is 28.

It can be divided in two parts, 143123 and 321341, that added together give a palindrome (464464).

The spelling of 143123321341 in words is "one hundred forty-three billion, one hundred twenty-three million, three hundred twenty-one thousand, three hundred forty-one".