Base | Representation |
---|---|
bin | 10100110100111100001… |
… | …001011100110111000010 |
3 | 12001211021002210202201001 |
4 | 110310330021130313002 |
5 | 141422131201020114 |
6 | 3013255515002214 |
7 | 205255202433412 |
oct | 24647411346702 |
9 | 5054232722631 |
10 | 1431233220034 |
11 | 501a89927832 |
12 | 1b147113936a |
13 | a4c70624c67 |
14 | 4d3b4750642 |
15 | 2736a187374 |
hex | 14d3c25cdc2 |
1431233220034 has 8 divisors (see below), whose sum is σ = 2187356430780. Its totient is φ = 702114409776.
The previous prime is 1431233220031. The next prime is 1431233220073. The reversal of 1431233220034 is 4300223321341.
It is a happy number.
It can be written as a sum of positive squares in 2 ways, for example, as 1424549667025 + 6683553009 = 1193545^2 + 81753^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×14312332200342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1431233219984 and 1431233220011.
It is not an unprimeable number, because it can be changed into a prime (1431233220031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6751099989 + ... + 6751100200.
Almost surely, 21431233220034 is an apocalyptic number.
1431233220034 is a deficient number, since it is larger than the sum of its proper divisors (756123210746).
1431233220034 is a wasteful number, since it uses less digits than its factorization.
1431233220034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13502200244.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 1431233220034 its reverse (4300223321341), we get a palindrome (5731456541375).
The spelling of 1431233220034 in words is "one trillion, four hundred thirty-one billion, two hundred thirty-three million, two hundred twenty thousand, thirty-four".
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