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1431233220034 = 25313502200189
BaseRepresentation
bin10100110100111100001…
…001011100110111000010
312001211021002210202201001
4110310330021130313002
5141422131201020114
63013255515002214
7205255202433412
oct24647411346702
95054232722631
101431233220034
11501a89927832
121b147113936a
13a4c70624c67
144d3b4750642
152736a187374
hex14d3c25cdc2

1431233220034 has 8 divisors (see below), whose sum is σ = 2187356430780. Its totient is φ = 702114409776.

The previous prime is 1431233220031. The next prime is 1431233220073. The reversal of 1431233220034 is 4300223321341.

It is a happy number.

It can be written as a sum of positive squares in 2 ways, for example, as 1424549667025 + 6683553009 = 1193545^2 + 81753^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×14312332200342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1431233219984 and 1431233220011.

It is not an unprimeable number, because it can be changed into a prime (1431233220031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6751099989 + ... + 6751100200.

Almost surely, 21431233220034 is an apocalyptic number.

1431233220034 is a deficient number, since it is larger than the sum of its proper divisors (756123210746).

1431233220034 is a wasteful number, since it uses less digits than its factorization.

1431233220034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13502200244.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 1431233220034 its reverse (4300223321341), we get a palindrome (5731456541375).

The spelling of 1431233220034 in words is "one trillion, four hundred thirty-one billion, two hundred thirty-three million, two hundred twenty thousand, thirty-four".

Divisors: 1 2 53 106 13502200189 27004400378 715616610017 1431233220034