Base | Representation |
---|---|
bin | 1101000001000101100111… |
… | …1101110111101011011111 |
3 | 1212200020122121112100010222 |
4 | 3100101121331313223133 |
5 | 3333443133121440333 |
6 | 50234555354151555 |
7 | 3005014065210626 |
oct | 320213175675337 |
9 | 55606577470128 |
10 | 14312340421343 |
11 | 4618914056108 |
12 | 17319b1a225bb |
13 | 7ca8565c8703 |
14 | 376a144c46bd |
15 | 19c46bb73298 |
hex | d0459f77adf |
14312340421343 has 2 divisors, whose sum is σ = 14312340421344. Its totient is φ = 14312340421342.
The previous prime is 14312340421307. The next prime is 14312340421367. The reversal of 14312340421343 is 34312404321341.
It is a strong prime.
It is an emirp because it is prime and its reverse (34312404321341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14312340421343 - 220 = 14312339372767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14312340421243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156170210671 + 7156170210672.
It is an arithmetic number, because the mean of its divisors is an integer number (7156170210672).
Almost surely, 214312340421343 is an apocalyptic number.
14312340421343 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312340421343 is an equidigital number, since it uses as much as digits as its factorization.
14312340421343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 14312340421343 its reverse (34312404321341), we get a palindrome (48624744742684).
The spelling of 14312340421343 in words is "fourteen trillion, three hundred twelve billion, three hundred forty million, four hundred twenty-one thousand, three hundred forty-three".
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