Base | Representation |
---|---|
bin | 100000100010101110101001… |
… | …100101010101001010110011 |
3 | 200202202112011110021222021102 |
4 | 200202232221211111022303 |
5 | 122224421013311341042 |
6 | 1224222135413315015 |
7 | 42101241100034666 |
oct | 4042565145251263 |
9 | 622675143258242 |
10 | 143124040340147 |
11 | 41670623599429 |
12 | 14076493635a6b |
13 | 61b2701501979 |
14 | 274b351d816dd |
15 | 1182eb8778b32 |
hex | 822ba99552b3 |
143124040340147 has 2 divisors, whose sum is σ = 143124040340148. Its totient is φ = 143124040340146.
The previous prime is 143124040340117. The next prime is 143124040340297. The reversal of 143124040340147 is 741043040421341.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143124040340147 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 143124040340147.
It is not a weakly prime, because it can be changed into another prime (143124040340117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71562020170073 + 71562020170074.
It is an arithmetic number, because the mean of its divisors is an integer number (71562020170074).
Almost surely, 2143124040340147 is an apocalyptic number.
143124040340147 is a deficient number, since it is larger than the sum of its proper divisors (1).
143124040340147 is an equidigital number, since it uses as much as digits as its factorization.
143124040340147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 38.
Adding to 143124040340147 its reverse (741043040421341), we get a palindrome (884167080761488).
The spelling of 143124040340147 in words is "one hundred forty-three trillion, one hundred twenty-four billion, forty million, three hundred forty thousand, one hundred forty-seven".
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