Base | Representation |
---|---|
bin | 100000100010110000110110… |
… | …100011011111010111000011 |
3 | 200202202202021021122202021122 |
4 | 200202300312203133113003 |
5 | 122224440334243220214 |
6 | 1224223210221542455 |
7 | 42101353516064411 |
oct | 4042606643372703 |
9 | 622682237582248 |
10 | 143126405445059 |
11 | 41671627637793 |
12 | 14076a33714a2b |
13 | 61b29ba4c052a |
14 | 274b4d811a2b1 |
15 | 11830a620a88e |
hex | 822c368df5c3 |
143126405445059 has 2 divisors, whose sum is σ = 143126405445060. Its totient is φ = 143126405445058.
The previous prime is 143126405445053. The next prime is 143126405445071. The reversal of 143126405445059 is 950544504621341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143126405445059 - 24 = 143126405445043 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 143126405445059.
It is not a weakly prime, because it can be changed into another prime (143126405445053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71563202722529 + 71563202722530.
It is an arithmetic number, because the mean of its divisors is an integer number (71563202722530).
Almost surely, 2143126405445059 is an apocalyptic number.
143126405445059 is a deficient number, since it is larger than the sum of its proper divisors (1).
143126405445059 is an equidigital number, since it uses as much as digits as its factorization.
143126405445059 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368000, while the sum is 53.
The spelling of 143126405445059 in words is "one hundred forty-three trillion, one hundred twenty-six billion, four hundred five million, four hundred forty-five thousand, fifty-nine".
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