143130040444340 has 48 divisors (see below), whose sum is σ = 301417905970944. Its totient is φ = 57091323120000.

The previous prime is 143130040444267. The next prime is 143130040444351. The reversal of 143130040444340 is 43444040031341.

It is a self number, because there is not a number n which added to its sum of digits gives 143130040444340.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3130655 + ... + 17206425.

It is an arithmetic number, because the mean of its divisors is an integer number (6279539707728).

Almost surely, 2^{143130040444340} is an apocalyptic number.

143130040444340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

143130040444340 is an abundant number, since it is smaller than the sum of its proper divisors (158287865526604).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143130040444340 is a wasteful number, since it uses less digits than its factorization.

143130040444340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14077208 (or 14077206 counting only the distinct ones).

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 143130040444340 its reverse (43444040031341), we get a palindrome (186574080475681).

The spelling of 143130040444340 in words is "one hundred forty-three trillion, one hundred thirty billion, forty million, four hundred forty-four thousand, three hundred forty".