Base | Representation |
---|---|
bin | 1101000001001000001010… |
… | …1010111011010010001111 |
3 | 1212200022102012112020200102 |
4 | 3100102002222323102033 |
5 | 3334001032432234411 |
6 | 50235151231121315 |
7 | 3005040026601455 |
oct | 320220252732217 |
9 | 55608365466612 |
10 | 14313023321231 |
11 | 4619134585988 |
12 | 1731b6267323b |
13 | 7ca934c2b59b |
14 | 376a7b08a9d5 |
15 | 19c4abab8d3b |
hex | d0482abb48f |
14313023321231 has 2 divisors, whose sum is σ = 14313023321232. Its totient is φ = 14313023321230.
The previous prime is 14313023321189. The next prime is 14313023321257. The reversal of 14313023321231 is 13212332031341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14313023321231 is a prime.
It is a super-2 number, since 2×143130233212312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14313023321194 and 14313023321203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14313023321281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156511660615 + 7156511660616.
It is an arithmetic number, because the mean of its divisors is an integer number (7156511660616).
Almost surely, 214313023321231 is an apocalyptic number.
14313023321231 is a deficient number, since it is larger than the sum of its proper divisors (1).
14313023321231 is an equidigital number, since it uses as much as digits as its factorization.
14313023321231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 14313023321231 its reverse (13212332031341), we get a palindrome (27525355352572).
The spelling of 14313023321231 in words is "fourteen trillion, three hundred thirteen billion, twenty-three million, three hundred twenty-one thousand, two hundred thirty-one".
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