Base | Representation |
---|---|
bin | 1000010101001101001… |
… | …0001111001010101110 |
3 | 111200110001121211221021 |
4 | 2011103102033022232 |
5 | 4321113042213124 |
6 | 145430434324354 |
7 | 13224632133433 |
oct | 2052322171256 |
9 | 450401554837 |
10 | 143131210414 |
11 | 55779922945 |
12 | 238a64296ba |
13 | 106604c6c1a |
14 | 6cdb42bb8a |
15 | 3acaa827e4 |
hex | 215348f2ae |
143131210414 has 4 divisors (see below), whose sum is σ = 214696815624. Its totient is φ = 71565605206.
The previous prime is 143131210399. The next prime is 143131210463. The reversal of 143131210414 is 414012131341.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35782802602 + ... + 35782802605.
It is an arithmetic number, because the mean of its divisors is an integer number (53674203906).
Almost surely, 2143131210414 is an apocalyptic number.
143131210414 is a deficient number, since it is larger than the sum of its proper divisors (71565605210).
143131210414 is an equidigital number, since it uses as much as digits as its factorization.
143131210414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71565605209.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 143131210414 its reverse (414012131341), we get a palindrome (557143341755).
The spelling of 143131210414 in words is "one hundred forty-three billion, one hundred thirty-one million, two hundred ten thousand, four hundred fourteen".
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