Search a number
-
+
1431320101201 is a prime number
BaseRepresentation
bin10100110101000001010…
…100111000000101010001
312001211111011021210021001
4110311001110320011101
5141422320421214301
63013312301102001
7205260306056314
oct24650124700521
95054434253231
101431320101201
11502023978951
121b1496257901
13a4c85624433
144d3c20c897b
1527372ae9c01
hex14d41538151

1431320101201 has 2 divisors, whose sum is σ = 1431320101202. Its totient is φ = 1431320101200.

The previous prime is 1431320101199. The next prime is 1431320101219. The reversal of 1431320101201 is 1021010231341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 855580600576 + 575739500625 = 924976^2 + 758775^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431320101201 - 21 = 1431320101199 is a prime.

Together with 1431320101199, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1431320101231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715660050600 + 715660050601.

It is an arithmetic number, because the mean of its divisors is an integer number (715660050601).

Almost surely, 21431320101201 is an apocalyptic number.

It is an amenable number.

1431320101201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431320101201 is an equidigital number, since it uses as much as digits as its factorization.

1431320101201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1431320101201 its reverse (1021010231341), we get a palindrome (2452330332542).

The spelling of 1431320101201 in words is "one trillion, four hundred thirty-one billion, three hundred twenty million, one hundred one thousand, two hundred one".