Base | Representation |
---|---|
bin | 100000100010110110000110… |
… | …100010000001000001001011 |
3 | 200202210021211010012201211002 |
4 | 200202312012202001001023 |
5 | 122230033410301000321 |
6 | 1224225541421125215 |
7 | 42101643302534555 |
oct | 4042660642010113 |
9 | 622707733181732 |
10 | 143132042203211 |
11 | 41673a5a4195a6 |
12 | 14077b473b980b |
13 | 61b33a8247a99 |
14 | 274b8b09b24d5 |
15 | 11832d5ee120b |
hex | 822d8688104b |
143132042203211 has 2 divisors, whose sum is σ = 143132042203212. Its totient is φ = 143132042203210.
The previous prime is 143132042203153. The next prime is 143132042203217. The reversal of 143132042203211 is 112302240231341.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143132042203211 - 222 = 143132038008907 is a prime.
It is not a weakly prime, because it can be changed into another prime (143132042203217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71566021101605 + 71566021101606.
It is an arithmetic number, because the mean of its divisors is an integer number (71566021101606).
Almost surely, 2143132042203211 is an apocalyptic number.
143132042203211 is a deficient number, since it is larger than the sum of its proper divisors (1).
143132042203211 is an equidigital number, since it uses as much as digits as its factorization.
143132042203211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 143132042203211 its reverse (112302240231341), we get a palindrome (255434282434552).
The spelling of 143132042203211 in words is "one hundred forty-three trillion, one hundred thirty-two billion, forty-two million, two hundred three thousand, two hundred eleven".
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