1431321011201 has 2 divisors, whose sum is σ = 1431321011202. Its totient is φ = 1431321011200.

The previous prime is 1431321011137. The next prime is 1431321011203. The reversal of 1431321011201 is 1021101231341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1428799464976 + 2521546225 = 1195324^2 + 50215^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431321011201 - 2⁶ = 1431321011137 is a prime.

Together with 1431321011203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1431321011203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715660505600 + 715660505601.

It is an arithmetic number, because the mean of its divisors is an integer number (715660505601).

Almost surely, 2^{1431321011201} is an apocalyptic number.

It is an amenable number.

1431321011201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431321011201 is an equidigital number, since it uses as much as digits as its factorization.

1431321011201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1431321011201 its reverse (1021101231341), we get a palindrome (2452422242542).

The spelling of 1431321011201 in words is "one trillion, four hundred thirty-one billion, three hundred twenty-one million, eleven thousand, two hundred one".