Base | Representation |
---|---|
bin | 101010101010000… |
… | …0110001001110000 |
3 | 10200202022011121120 |
4 | 1111110012021300 |
5 | 10412410101230 |
6 | 354010222240 |
7 | 50320054650 |
oct | 12524061160 |
9 | 3622264546 |
10 | 1431331440 |
11 | 674a49550 |
12 | 33b424980 |
13 | 19a6cb7a6 |
14 | d814a360 |
15 | 859d3310 |
hex | 55506270 |
1431331440 has 320 divisors, whose sum is σ = 5613069312. Its totient is φ = 293068800.
The previous prime is 1431331417. The next prime is 1431331459. The reversal of 1431331440 is 441331341.
It is a super-2 number, since 2×14313314402 = 4097419382264947200, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a self number, because there is not a number n which added to its sum of digits gives 1431331440.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1348510 + ... + 1349570.
Almost surely, 21431331440 is an apocalyptic number.
1431331440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1431331440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2806534656).
1431331440 is an abundant number, since it is smaller than the sum of its proper divisors (4181737872).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1431331440 is a wasteful number, since it uses less digits than its factorization.
1431331440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1168 (or 1162 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
The square root of 1431331440 is about 37832.9412020794. The cubic root of 1431331440 is about 1126.9727204832.
Adding to 1431331440 its reverse (441331341), we get a palindrome (1872662781).
Subtracting from 1431331440 its reverse (441331341), we obtain a palindrome (990000099).
It can be divided in two parts, 14313 and 31440, that added together give a triangular number (45753 = T302).
The spelling of 1431331440 in words is "one billion, four hundred thirty-one million, three hundred thirty-one thousand, four hundred forty".
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