143133435121 has 2 divisors, whose sum is σ = 143133435122. Its totient is φ = 143133435120.

The previous prime is 143133435119. The next prime is 143133435169. The reversal of 143133435121 is 121534331341.

143133435121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139547820721 + 3585614400 = 373561^2 + 59880^2 .

It is a cyclic number.

It is not a de Polignac number, because 143133435121 - 2¹ = 143133435119 is a prime.

Together with 143133435119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (143133435101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71566717560 + 71566717561.

It is an arithmetic number, because the mean of its divisors is an integer number (71566717561).

Almost surely, 2^143133435121 is an apocalyptic number.

It is an amenable number.

143133435121 is a deficient number, since it is larger than the sum of its proper divisors (1).

143133435121 is an equidigital number, since it uses as much as digits as its factorization.

143133435121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12960, while the sum is 31.

Adding to 143133435121 its reverse (121534331341), we get a palindrome (264667766462).

The spelling of 143133435121 in words is "one hundred forty-three billion, one hundred thirty-three million, four hundred thirty-five thousand, one hundred twenty-one".