14313411102130 has 16 divisors (see below), whose sum is σ = 29444731410240. Its totient is φ = 4907455234992.

The previous prime is 14313411102119. The next prime is 14313411102143. The reversal of 14313411102130 is 3120111431341.

It is a junction number, because it is equal to n+sod(n) for n = 14313411102095 and 14313411102104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102238650660 + ... + 102238650799.

It is an arithmetic number, because the mean of its divisors is an integer number (1840295713140).

Almost surely, 2^{14313411102130} is an apocalyptic number.

14313411102130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14313411102130 is an abundant number, since it is smaller than the sum of its proper divisors (15131320308110).

14313411102130 is a wasteful number, since it uses less digits than its factorization.

14313411102130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204477301473.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 14313411102130 its reverse (3120111431341), we get a palindrome (17433522533471).

The spelling of 14313411102130 in words is "fourteen trillion, three hundred thirteen billion, four hundred eleven million, one hundred two thousand, one hundred thirty".