Base | Representation |
---|---|
bin | 1101000001001001101110… |
… | …1101100001101000101001 |
3 | 1212200100111111001010200121 |
4 | 3100102123231201220221 |
5 | 3334002413004324001 |
6 | 50235301035403241 |
7 | 3005053320516226 |
oct | 320223355415051 |
9 | 55610444033617 |
10 | 14313443433001 |
11 | 461932a738099 |
12 | 173205b2b3521 |
13 | 7ca9a0c9212b |
14 | 376ababa894d |
15 | 19c4d39016a1 |
hex | d049bb61a29 |
14313443433001 has 12 divisors (see below), whose sum is σ = 14518429110016. Its totient is φ = 14111312511240.
The previous prime is 14313443432957. The next prime is 14313443433031. The reversal of 14313443433001 is 10033434431341.
It is not a de Polignac number, because 14313443433001 - 215 = 14313443400233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14313443433031) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 239553736 + ... + 239613478.
Almost surely, 214313443433001 is an apocalyptic number.
It is an amenable number.
14313443433001 is a deficient number, since it is larger than the sum of its proper divisors (204985677015).
14313443433001 is an frugal number, since it uses more digits than its factorization.
14313443433001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107412 (or 107341 counting only the distinct ones).
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 14313443433001 its reverse (10033434431341), we get a palindrome (24346877864342).
The spelling of 14313443433001 in words is "fourteen trillion, three hundred thirteen billion, four hundred forty-three million, four hundred thirty-three thousand, one".
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