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14313499477 is a prime number
BaseRepresentation
bin11010101010010011…
…01010101101010101
31100221112101010000021
431111021222231111
5213303223440402
610324151545141
71014462511114
oct152511525525
940845333007
1014313499477
116085663012
12293568b1b1
131471555324
1499ada1c7b
1558b90bd37
hex35526ab55

14313499477 has 2 divisors, whose sum is σ = 14313499478. Its totient is φ = 14313499476.

The previous prime is 14313499433. The next prime is 14313499553. The reversal of 14313499477 is 77499431341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14238694276 + 74805201 = 119326^2 + 8649^2 .

It is a cyclic number.

It is not a de Polignac number, because 14313499477 - 215 = 14313466709 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14313499177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156749738 + 7156749739.

It is an arithmetic number, because the mean of its divisors is an integer number (7156749739).

Almost surely, 214313499477 is an apocalyptic number.

It is an amenable number.

14313499477 is a deficient number, since it is larger than the sum of its proper divisors (1).

14313499477 is an equidigital number, since it uses as much as digits as its factorization.

14313499477 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2286144, while the sum is 52.

The spelling of 14313499477 in words is "fourteen billion, three hundred thirteen million, four hundred ninety-nine thousand, four hundred seventy-seven".